import re

input_str = """
G90*(((1000*F15/100+(10*(1+0.1)/(1+0.008))*37.6/100-(E3/(1+0.008))*0.98*A27/100*7.21/100*56/72-(D3/(1+0.008))*A19/100*(8.94/100*56/72+0.69/100*56/88))*((A3*(1-(C9+D9+H9+I9-0.5*G9*0.1)/100))+(4*(1-D11/100-H11/100+0.5*G11/100*0.1)))+(A3*B9/100+4*D11/100*112/160)*(((D3/(1+0.008))*(A19/100*(1-8.94/100-0.69/100)+C19/100*0.5*(1-0.1)))+((E3/(1+0.008))*0.98*(A27/100*(1-7.21/100)+0.5*F27/100*(1-0.1))+(E3/(1+0.008))*(1-0.98))-((10*(1+0.1)/(1+0.008))*(1-(8.35+44.44+31.73+0.5*0.222)/100))-(1000*(60/28*A15/100+71/55*B15/100+142/62*C15/100+0.5*D15/100))))/((A3*B9/100+4*D11/100*112/160)*(1-C37/100)-((A3*(1-(C9+D9+H9+I9-0.5*G9*0.1)/100))+(4*(1-D11/100-H11/100+0.5*G11/100*0.1)))*C37/100*56/72))
"""

"""
[a-zA-Z] 字母开头
\d{2,3} 匹配后2-3位的数字
"""
result = re.findall(r'[a-zA-Z]\d{2,3}', input_str)
print(result)